400=(-4x^2)+80x

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Solution for 400=(-4x^2)+80x equation: 



400=(-4x^2)+80x

We move all terms to the left:

400-((-4x^2)+80x)=0



We calculate terms in parentheses: -((-4x^2)+80x), so:

(-4x^2)+80x

We get rid of parentheses

-4x^2+80x

Back to the equation:

-(-4x^2+80x)



We get rid of parentheses

4x^2-80x+400=0

a = 4; b = -80; c = +400;
Δ = b2-4ac
Δ = -802-4·4·400
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{80}{8}=10$

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